# Output of python program | Set 13(Lists and Tuples)

**Prerequisite: **Lists and Tuples

**1) What is the output of the following program?**

## PYTHON

`List` `=` `[` `True` `, ` `50` `, ` `10` `]` `List` `.insert(` `2` `, ` `5` `) ` `print` `(` `List` `, ` `"Sum is: "` `, ` `sum` `(` `List` `))` |

a) [True, 50, 10, 5] Sum is: 66

b) [True, 50, 5, 10] Sum is: 65

c) TypeError: unsupported operand type(s) for +: ‘int’ and ‘str’

d) [True, 50, 5, 10] Sum is: 66

**Ans. (d)** **Explanation: **The List is initially has 3 elements. The insert() adds element 5 at index 2, moving element 10 at index 3 and the List becomes [True, 50, 5, 10]. Boolean has an integer value of 1, thus sum becomes 1 + 50 + 5 + 10 = 66.

**2) What is the output of the following program?**

## PYTHON

`T ` `=` `(` `1` `, ` `2` `, ` `3` `, ` `4` `, ` `5` `, ` `6` `, ` `7` `, ` `8` `)` `print` `(T[T.index(` `5` `)], end ` `=` `" "` `)` `print` `(T[T[T[` `6` `]` `-` `3` `]` `-` `6` `])` |

a) 4 0

b) 5 8

c) 5 IndexError

d) 4 1

**Ans. (b)** **Explanation: **The inbuilt function index() returns the index of the element. T.index(5) = 4 and T[4] = 5. The other print statement has indexing of tuples, similar to that of Lists. T[6] = 7, T[6]-3 = 4, T[T[6]-3] = 5, T[T[6]-3]-6 = -1 and T[T[T[6]-3]-6], i.e. T[-1] = 8.

**3) What is the output of the following program?**

## PYTHON

`L ` `=` `[` `1` `, ` `3` `, ` `5` `, ` `7` `, ` `9` `]` `print` `(L.pop(` `-` `3` `), end ` `=` `' '` `)` `print` `(L.remove(L[` `0` `]), end ` `=` `' '` `)` `print` `(L)` |

a) 5 None [3, 7, 9]

b) 5 1 [3, 7, 9]

c) 5 1 [3, 7, 9]

d) 5 None [1, 3, 7, 9]

**Ans. (a)** **Explanation: **pop() will delete and return the element whose index was passed as parameter. L.pop(-3) will delete 5 and return 5, which is printed by print(). remove() does return any value, it’s a void function. L[0] = 1, L.remove(1) will delete 1 from the list and the list remains to be [3, 7, 9].

**4) What is the output of the following program?**

## PYTHON

`def` `REVERSE(L):` ` ` `L.reverse()` ` ` `return` `(L)` `def` `YKNJS(L):` ` ` `List` `=` `[]` ` ` `List` `.extend(REVERSE(L))` ` ` `print` `(` `List` `)` `L ` `=` `[` `1` `, ` `3.1` `, ` `5.31` `, ` `7.531` `]` `YKNJS(L)` |

a) [1, 3.1, 5.31, 7.531]

b) [7.531, 5.31, 3.1, 1]

c) IndexError

d) AttributeError: ‘NoneType’ object has no attribute ‘REVERSE’

**Ans. (b)** **Explanation: **REVERSE() reverses the list and returns it. YKNJS() adds reverse of a list L to the empty list List. L = [1, 3.1, 5.31, 7.531], gets reversed and becomes [7.531, 5.31, 3.1, 1].

**5) What is the output of the following program?**

## PYTHON

`from` `math ` `import` `sqrt` `L1 ` `=` `[x` `*` `*` `2` `for` `x ` `in` `range` `(` `10` `)].pop()` `L1 ` `+` `=` `19` `print` `(sqrt(L1), end ` `=` `" "` `)` `L1 ` `=` `[x` `*` `*` `2` `for` `x ` `in` `reversed` `(` `range` `(` `10` `))].pop()` `L1 ` `+` `=` `16` `print` `(` `int` `(sqrt(L1)))` |

a) 10.0 4.0

b) 4.3588 4

c) 10 .0 4

d) 10.0 0

**Ans. (c)** **Explanation:** The first list compression will create list as [0, 1, 4, 9, 16, 25, 36, 49, 64, 81] and pop() will return 81. 81 + 19 = 100, whose square root is 10.0 and similarly in 2nd case pop() will return 0 due to the reversed range and integer value of square root of 16 is 4.

This article is contributed by **Piyush Doorwar**. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.